tentukan nilai x pada gambar berikut

[tex] \frac{4 \sqrt{3} }{ \sin(45) } = \frac{x}{ \sin(120) } \\ x = \frac{ \sin(120) \times 4 \sqrt{3} }{ \sin(45) } = \frac{ \frac{ \sqrt{3} }{2} \times 4 \sqrt{3} }{ \frac{1}{2} \sqrt{2} } = 6 \sqrt{2} [/tex]
[tex] \tan(30) = \frac{y}{4} = \frac{x}{y} = \frac{1}{ \sqrt{3} } \\ y = \frac{4}{3} \sqrt{3} \\ x = \frac{4}{3} [/tex]