BANTU! 1. Dik = <AOB = 90derajat r = 21 cm Dit = Luas tembereng! Jawab?

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1 Jawaban

  • Luas segitiga AOB
    [tex] = \frac{1}{2} \times 21 \times 21 \\ = 220.5 {cm}^{2}[/tex]

    Luas juring AOB
    [tex] = \frac{ {90}^{0} }{ {360}^{0} } \times \frac{22}{7} \times {21}^{2} \\ = \frac{1}{4} \times \frac{22}{7} \times 441 \\ = 346.5 {cm}^{2} [/tex]

    Luas tembereng AB
    [tex] = 346.5 {cm}^{2} - 220.5{cm}^{2} \\ = 126 {cm}^{2} [/tex]

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