mohon dibantu kk.. no.6-8 pakai jalan caranya ya..

no.6
[tex]sin \: 210 = - \frac{1}{2} \\ cos \: 330 = \frac{1}{2} \\ sin( - 240) = \frac{1}{2} \sqrt{3 }[/tex]
sin (-240). cos 330. sin 210=
[tex] \frac{1}{2} \sqrt{3} \times \frac{1}{2} \times( - \frac{1}{2} ) = - \frac{1}{8} \sqrt{ 3} [/tex]

no. 8
[tex]cos \: 240 = - \frac{1}{2} \\ sin \: 240 = - \frac{1}{2} \sqrt{3} [/tex]


jadi -1/2 . -1/2 akar 3
sama dengan 1/4 akar 3