Matematika

Pertanyaan

bentuk sederhana dan rasional dari bilangan 12 per 6+√2

2 Jawaban

  • [tex] \frac{12}{6 + \sqrt{2} } \times \frac{6 - \sqrt{2} }{6 - \sqrt{2} } = \frac{72 - 12 \sqrt{2} }{34} = \frac{36 - 6\sqrt{2} }{17} [/tex]
    Good Luck.
  • [tex] \frac{12}{6+ \sqrt{2} } x \frac{6- \sqrt{2} }{6- \sqrt{2} } = \frac{12(6- \sqrt{2}) }{34}= \frac{6(6- \sqrt{2}) }{17} = \frac{36-6 \sqrt{2} }{17} [/tex]

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