sebuah lingkaran bersudut pusat 120° dengan jari jari 14 cm, tentukan panjang busur dan juring lingkaran nya

Penyelesaian:
Diket.:
α = 120°
r = 14 cm
Ditanya:
Panjang busur = ....?
Luas juring = ....?
Jawab:
Panjang busur
= α/360° × 2πr
= 120°/360° × 2 × 22/7 × 14
= 1/3 × 616/7
= 616/21
= 29,33 cm

Luas juring
= α/360° × πr²
= 120°/360° × 22/7 × 14²
= 1/3 × 22/7 × 196
= 4.312/21
= 205,33 cm²

Semoga bisa membantu...

panjang busur
[tex] \frac{120}{360} \times \frac{22}{7} \times 28[/tex]
[tex] \frac{1}{3} \times (22 \times 4) = \frac{88}{3} = 29.3[/tex]
luas juring
[tex] \frac{120}{360} \times \frac{22}{7} \times {14}^{2} = \frac{22}{21} \times 196[/tex]
[tex] \frac{22 \times 196}{21} = 205.3[/tex]