bila x1 dan x2 adalah akar-akar persamaan kuadrat x²-6x+2=0 nilai dari 1 per x1+1per x2

PK ≡ [tex] x^{2} -6x +2 =0[/tex]

a=1
b= -6
c=2

x1 +x2 = -b/a = -(-6)/1 = 6
x1 × x2 = c/a = 2/1 = 2

[tex]= \frac{1}{ x_{1} } + \frac{1}{ x_{2} } [/tex]

[tex]= \frac{ x_{1} }{ x_{1} x_{2} } + \frac{ x_{2} }{ x_{1} x_{2} } [/tex]

[tex]= \frac{ x_{1} + x_{2} }{ x_{1} x_{2} } [/tex]

= [tex] \frac{6}{2} [/tex]

= 3