Akar 6 di bagi 3akar2+2akar2

Mapel : Matematika

Kelas : 9

Bab : Akar dan Pangkat
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[tex] = \frac{ \sqrt{6} }{3 \sqrt{2} + 2 \sqrt{2} } \times \frac{3 \sqrt{2} - 2 \sqrt{2} }{3\sqrt{2} - 2 \sqrt{2} } \\ \\ = \frac{3 \sqrt{12} - 2 \sqrt{12} }{18 - 8} \\ \\ = \frac{6 \sqrt{2} - 4 \sqrt{2} }{10} \\ \\ = \sqrt{2} ( \frac{3}{5} - \frac{2}{5} )[/tex]