tentukan PH larutan 0,001 mol Ca(OH)2 dalam 2 L larutan

2 liter = 2000 ml
Ca(OH)2 --> Ca2+ + 2OH
valensi basa = 2

M = n × 1000/v
M = 0.001 × 1000/2000
M = 5 × 10^-4

[OH-] = M × valensi basa
[OH-] = 5×10^-4 × 2
[OH-] = 10^-3

pOH = -log[OH-]
pOH = -log10^-3
pOH = 3

pH = 14-3 = 11

jadi phnya 11