jika y = √2x +6, maka f' (x)

 y = [tex] \sqrt{2x+6} [/tex]
f(x) = 2x+6 f"(x) = 2
kalau turunannya n [f(x)]n-1 . f'(x)
rumusnya
[tex] \frac{dy}{dx} = \frac{1}{2} (2x+6)^{\frac{1}{2}-1} (2)[/tex]
[tex]\frac{dy}{dx} = (2x+6)^{-\frac{1}{2}} [/tex]