Nilai dari 6log81.3log1per625.akar5log36adalah

[tex] = 6log81.3log \frac{1}{625} . \sqrt{5} log36 \\ = 6log {3}^{4} .3log {5}^{ - 4} . {5}^{ \frac{1}{2} } log {6}^{2} \\ = (4)6log3.( - 4)3log5.( \frac{ \frac{1}{2} }{2} )5log6 \\ = (4 \times ( - 4) \times \frac{1}{4} ) \times 6log3.3log5.5log6 \\ = (4 \times (- 4) \times \frac{1}{4} ) \times 1 \\ = - 4[/tex]