tolong bantu dong please. jika cos a= 3/5, berapakah sin a, tan b, dan sec a. makasii

cos a = samping / miring = 3/5

depan= √miring²-samping² = √5²-3² = 4

sin a = depan / miring = 4/5
tan a = depan / samping = 5/3
sec a = 1 / cos a = 1 / 3/4 = 4/3