Interval nilai x agar grafik f(x) = 4x3 + 6x2 – 24x + 10 turun adalah … A -2 < x < -1 B -1 < x < 2 C -2 < x < 1 D x < -2 atau x > -1 E x < -2 atau x >1 Save &

[tex]f(x) = {4x}^{3} + {6x}^{2} - 24x + 10 \\ f'(x) = 12 {x}^{2} + 12x - 24 \\ \\ f'(x) < 0 \\ {12x}^{2} + 12x - 24 = 0 \\ {x}^{2} + x - 12 = 0 \\ (x + 2)( x - 1) = 0 \\x + 2 = 0 \: atau \: x - 1 = 0 \\ x = - 2 \: atau \: x = 1 \\ \\ Interval \: x \: agar \: kurva \: turun \: - 2 < x < 1[/tex]