tolong ya pakai cara

rumus diagonal D=s^2+s^2
d=4O+4O
=8Ocm^2
jwabanx A

smga mmbntu

rumusnya
[tex]k = 4 \times s[/tex]
[tex]40 = 4 \times s \\ \frac{40}{4} = s \\ 10 = s[/tex]
setelah sisi persegi kita temukan 10 cm maka dimasukkan dalan rumus phytagoras
[tex]diagonal = \sqrt{ {10}^{2} + {10}^{2} } \\ diagonal = \sqrt{100 + 100} \\ diagonal = \sqrt{200}[/tex]