tolong caranya gimna??

[tex] \frac{bc}{ \sin(60) }= \frac{24}{ \sin(45) } \\ bc = \frac{24 \times \sin(60) }{ \sin(45) } = \frac{24 \times \frac{ \sqrt{3} }{2} }{ \frac{1}{2} \sqrt{2} } = 12 \sqrt{6} [/tex]