25 ML larutan CH3COOH 0,2 M. 25 ML larutan KOH 0,1 M. ka=1x10-^5 Ph?
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25 ML larutan CH3COOH 0,2 M. 25 ML larutan KOH 0,1 M. ka=1x10-^5 Ph?
1 Jawaban
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1. Jawaban nugroho528
Mol ch3cooh = 25 x 0,2 = 5 mmol
Mol koh = 25 x 0,1 = 2,5 mmol
ch3cooh + koh => ch3cook + h2o
5. 2,5. - -
2,5. 2,5. 2,5. 2,5
2,5. - 2,5. 2,5
[H+] = Ka (mol ch3cooh/mol ch3coo-)
= 10^-5 (2,5/2,5) = 10^-5
pH = - log 10^-5 = 5