Tolong dijawab dijelaskan beserta caranya

(f o f) = f(f(x))
(f o f) = f(2/(x - 2))
(f o f) = 2/(2/(x - 2) - 2)
y = 2/(2 - 2 (x - 2))/(x - 2))
y = 2/((2 - 2x + 4)/(x - 2))
y = 2/((6 - 2x)/(x - 2))
y = 2 . (x - 2)/(6 - 2x)
y = 2 . (x - 2)/(2 . (3 - x))
y = (x - 2)/(- x + 3)
y⁻¹ = (-3x - 2)/(-x - 1)
(f o f)⁻¹ = (3x + 2)/(x + 1)

Mapel : Matematika

Kelas : 10

Bab : Relasi dan Fungsi
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Misalkan
x + 2 = y

x = y - 2

Maka, Nilai fungsi f(x)
f(x) = 2/(x - 2)

⏩Tentukan nilai invers f(x)

Misalkan

2/(x - 2) = y
2 = yx - 2y
-yx = -2y - 2

yx = 2y + 2
x = (2y + 2)/y

Maka :
f-¹(x) = (2x + 2)/x

Sehingga :

(f-¹o f-¹) (x) = f-¹(2x + 2/x)

= [2(2x + 2/x) + 2] /(2x + 2)/x

= 6x + 4/x • x /2x + 2

= 6x² + 4x/2x² + 2x

= 2x(3x + 2)/2x(x + 1)

= 3x + 2/x + 1 → Opsi D