turunan pertama dari f(x) = (3x^2 + 2) (x + 1)

f(x)=U.V => f'(x)=U'V+V'U
f(x)=(3x²+2)(x+1)
U=3x²+2 => U'= 6x
V=x+1 => V'=1
f'(x)=6x(x+1)+1(3x²+2)=6x²+6x+3x²+2=9x²+6x+2