jika panjang AB=12 cm dan panjang TF = 10 cm , hitunglah volume limas tersebut! pliss tolong>.<

cari panjang TE dulu, selaku tinggi Limas
[tex]x = \sqrt{ {10}^{2} - {6}^{2}} \\ = \sqrt{100 - 36} \\ = \sqrt{64} = 8[/tex]
maka volume Limas = L alas x tinggi
[tex] = (12 \times 12) \times 8 \\ = 144 \times 8 \\ = 1152 \: {cm}^{3} [/tex]

karena berbentuk lancip atas maka x 1/3
=384

panjang TE
[tex] = \sqrt{ {10}^{2} } - {6}^{2} \\ = \sqrt{100} - 36 \\ = \sqrt{64 } \\ = 8 \: cm[/tex]
V.Limas
[tex] = \frac{1}{3} \times {s}^{2} \times t \\ = \frac{1}{3} \times {12}^{2} \times 8 \\ = \frac{1}{3} \times 144 \times 8 \\ = 384 \: {cm}^{3} [/tex]