x pangkat dua-16/x:x+4/3x =...

[tex]\displaystyle \frac{x^2-16}{x}:\frac{x+4}{3x}=\frac{(x+4)(x-4)}{x}\times\frac{3x}{x+4} \\ \\ \frac{x^2-16}{x}:\frac{x+4}{3x}=3(x-4) \\ \\ \frac{x^2-16}{x}:\frac{x+4}{3x}=3x-12[/tex]