Matematika

Pertanyaan

bisa di bantu jawabkan soal saya no.29-30
bisa di bantu jawabkan soal saya no.29-30

1 Jawaban

  • 29.
    [tex]y=kx \\ x^2+y^2-4x-2y+4=0 \\ x^2+(kx)^2-4x-2(kx)+4=0 \\ x^2+k^2x^2-4x-2kx+4=0 \\ (k^2+1)x^2-2(k+2)x+4=0 \\ $Memotong, $D>0 \\ b^2-4ac>0 \\ (-2(k+2))^2-4(k^2+1).4>0 \\ 4k^2+16k+16-16k^2-16>0 \\ -12k^2+16k>0 \\ 3k^2-4k<0 \\ k(3k-4)<0 \\ 0<k<\frac{4}{3} \\ $Pilihan : $B [/tex]

    30.
    [tex]x^2+y^2-2x-6y-7=0 \\ x^2-2x+1+y^2-6y+9=17 \\ (x-1)^2+(y-3)^2=17 \\ $Garis singgung melalui $(5,k) \\ 4^2+(y-3)^2=17 \\ (y-3)^2=1 \\ y-3=\pm 1 \\ y_1=2 \\ y_2=4 \\ $Garis ke-1:$ \\ (5-1)(x-1)+(2-3)(y-3)=17 \\ 4(x-1)-(y-3)=17 \\ 4x-4-y+3=17 \\ 4x-y-18=0 \\ \\ $Garis ke-2:$ \\ (5-1)(x-1)+(4-3)(y-3)=17 \\ 4(x-1)+y-3=17 \\ 4x-4+y-3=17 \\ 4x+y-24=0 \\ $Jawaban di garis pertama : $E[/tex]