Matematika

Pertanyaan

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1 Jawaban

  • 1. C = 40
    R = 4/5 x 40
    = 32 derajat

    F = (9/5 x 40) + 32
    = 72 + 32
    = 104 derajat

    2. R = 40
    F = (9/4 x 40) + 32
    = 90 + 32
    = 122 derajat

    C = 5/4 x 40
    = 50 derajat

    3. F = 50
    C = 5/9 x (50-32)
    = 5/9 x 18
    = 10 derajat

    R = 4/9 x (50-32)
    = 4/9 x 18
    = 8 derajat

    4. C = 60
    R = 4/5 x 60
    = 48 derajat

    F = (9/5 x 60) + 32
    = 108 + 32
    = 140 derajat