panjang sisi pq = ..... cm

[tex]pq = \sqrt{ {26}^{2} - {24}^{2} } \\ = \sqrt{676 - 576} \\ = \sqrt{100} \\ = 10[/tex]

PQ^2=PR^2-QR^2
=26^2-24^2
=676-576
=100
PQ= akar 100 =10