Jika f (x) 2x+6 / 5x-8 maka f_1 (x)

f(x) = (2x + 6) / (5x - 8)
y = (2x + 6) / (5x - 8)
y (5x - 8) = (2x + 6)
5xy - 8y = 2x + 6
5xy - 2x = 8y + 6
x (5y - 2) = 8y + 6
x = (8y + 6) / (5y - 2)
f^-1(x) = (8x + 6) / (5x - 2)