diket=f(x)=px+q jika f(-3)=12 dan f(4)=26 maka nilai p+2q adalah
Matematika
risma823
Pertanyaan
diket=f(x)=px+q jika f(-3)=12 dan f(4)=26 maka nilai p+2q adalah
1 Jawaban
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1. Jawaban safiraaiueo
Jawab :
f(x) = px + q
f(-3) = p(-3) + q = -3p + q = 12
f(4) = p(4) + q = 4p + q = 26
-3p + q = 12
4p + q = 26
__________ -
-7p = -14
p = 2
4p + q = 26
4(2) + q = 26
8 + q = 26
q = 26 - 8
q = 18
f(x) = px + q = 2x + 18
Nilai p + 2q
= 2 + 2 × 18
= 38