Tolong bantu aku dong buat cara nomer 8 dan 9 aku lupa caranya

[tex]2 {x}^{2} - 3x + 6 = 0 \\ \alpha + \beta = \frac{3}{2} \\ \alpha . \beta = 3 \\ \alpha + 2 + \beta + 2 = \frac{3}{2} + 4 = \frac{11}{2} \\ ( \alpha + 2)( \beta + 2) = \alpha \beta + 2( \alpha + \beta ) + 4 = 3 + 2( \frac{3}{2} ) + 4 = 10 \\ pkb = {x}^{2} - ( \frac{11}{2} )x + 10 = 0 \\ 2 {x}^{2} - 11x + 20 = 0[/tex]
[tex]2 {x}^{2} - x + 3 = 0 \\ x1 + x2 = \frac{1}{2} \\ x1x2 = \frac{3}{2} \\ \frac{3x1}{x2} + \frac{3x2}{x1} = \frac{3 {x1}^{2} + 3 {x2}^{2} }{x1x2} = \\ \frac{3( {x1}^{2} + {x2}^{2} )}{x1x2} = \frac{3 {(x1 + x2)}^{2} - 2x1x2}{x1x2} = \\ \frac{3 { (\frac{1}{2} )}^{2} - 2. \frac{3}{2} }{ \frac{3}{2} } = \frac{ \frac{3}{4} - 3}{ \frac{3}{2} } = \frac{ \frac{ - 9}{4} }{ \frac{3}{2} } = \frac{ - 9}{4} \times \frac{2}{3} = - \frac{3}{2} [/tex]
smoga membantu.....