Jika f(x) = x^3-8/x-2 maka df(x)/dx =....

u = x^3-8, u' = 3x^2
v = x-2, v' = 1
d(f(x))/dx = (u'v - v'u)/v^2
= (3x^2(x-2) - (x^3-8))/(x-2)^2
= 2(x^3 - 3x^2 + 4) / (x - 2)^2

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