Diketahui f(x) = x + 3 dan f o g (x) = x2 + 6x + 7, mak g(-1) = . . . . a. 11 b. -1 c. 17 d. 2 e. 1

[tex]f og(x) = {x}^{2} + 6x + 7 \\ f(g(x)) = {x}^{2} + 6x + 7 \\ g(x) + 3 = {x}^{2} + 6x + 7 \\ g(x) = {x}^{2} + 6x + 7 - 3 \\ g(x) = {x}^{2} + 6x + 4 \\ g( - 1) = ( { - 1})^{2} + 6( - 1) + 4 \\ = 1 - 6 + 4 \\ = - 1[/tex]